Mini Parser- Medium - L
Published:
Question
- https://leetcode.com/problems/mini-parser/
Given a string s represents the serialization of a nested list, implement a parser to deserialize it and return the deserialized NestedInteger.
Each element is either an integer or a list whose elements may also be integers or other lists.
Approach
- Stack
Solution
/**
* // This is the interface that allows for creating nested lists.
* // You should not implement it, or speculate about its implementation
* class NestedInteger {
* public:
* // Constructor initializes an empty nested list.
* NestedInteger();
*
* // Constructor initializes a single integer.
* NestedInteger(int value);
*
* // Return true if this NestedInteger holds a single integer, rather than a nested list.
* bool isInteger() const;
*
* // Return the single integer that this NestedInteger holds, if it holds a single integer
* // The result is undefined if this NestedInteger holds a nested list
* int getInteger() const;
*
* // Set this NestedInteger to hold a single integer.
* void setInteger(int value);
*
* // Set this NestedInteger to hold a nested list and adds a nested integer to it.
* void add(const NestedInteger &ni);
*
* // Return the nested list that this NestedInteger holds, if it holds a nested list
* // The result is undefined if this NestedInteger holds a single integer
* const vector<NestedInteger> &getList() const;
* };
*/
class Solution {
public:
NestedInteger deserialize(string s) {
stack<NestedInteger> stk({NestedInteger()});
for (size_t i = 0; i < s.size(); ++i) {
if (s[i] == '[') {
stk.push(NestedInteger());
}
else if (s[i] == ']') {
NestedInteger ni = stk.top();
stk.pop();
stk.top().add(ni);
}
else if (s[i] == ',') {
}
else {
int v = 0;
bool negative = false;
if (s[i] == '-') {
negative = true;
++i;
}
for (; i < s.size() && '0' <= s[i] && s[i] <= '9'; ++i) {
v = v * 10 + s[i] - '0';
}
if (negative) {
v = -v;
}
--i;
stk.top().add(NestedInteger(v));
}
}
return stk.top().getList().front();
}
};